The discussion centers on calculating the volume of KCl produced from the reaction 2KClO3 -----> 2KCl + 3O2. The correct volume of KCl is 2 dm³, as stated in the homework question, despite the calculation suggesting 44.8 dm³ based on the molar volume of gases. One mole of any gas occupies 22.4 dm³, leading to confusion regarding the interpretation of the question. Participants agree that the question is poorly worded and lacks sufficient context.
PREREQUISITESChemistry students, educators, and anyone involved in teaching or learning stoichiometry and chemical reaction calculations.
So is it incorrect statement? Because it is asked in my test. Do you think there is another way of thinking about the question? If this is wrong should I inform it to my teacher so they can cancel the question.Chestermiller said:What is the exact and complete problem statement?
I don't know. Maybe those are supposed to be both the numbers of moles in the balanced chemical equation and the actual numbers of moles involved. How did you get 44.8?Aafia said:So is it incorrect statement? Because it is asked in my test. Do you think there is another way of thinking about the question? If this is wrong should I inform it to my teacher so they can cancel the question.
one mole of any gas occupy volume of 22.4dm³ (molar volume) and from equation there are two moles of potassium chloride so volume will be 2×22.4dm³= 44.8dm³. I think they are asking about 2 moles of solid KCl. Is that right?Chestermiller said:I don't know. Maybe those are supposed to be both the numbers of moles in the balanced chemical equation and the actual numbers of moles involved. How did you get 44.8?
That would be my guess.Aafia said:one mole of any gas occupy volume of 22.4dm³ (molar volume) and from equation there are two moles of potassium chloride so volume will be 2×22.4dm³= 44.8dm³. I think they are asking about 2 moles of solid KCl. Is that right?