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## Homework Statement

Theres a lamp that absorbs 60 W when connected to a 120-V source.

Q: Find the cost of operating the lamp for 24 hrs when electricity cost 6.8cents/kWh.

## Homework Equations

current = power/voltage

## The Attempt at a Solution

1)I took a guess and said 60W equals in one second.

60W(60sec x 60min x 24hrs) = 5,184,000

2)Then, 24hrs into kW = 24000 kW in a day.

3)(5,184,000/24000) x 6.8 cents = 1468.8 cents.

I'm pretty sure I'm missing a formula for time. Thanks for any help.