Calculating Weight and Velocity on a Circular Track: Formulas and Examples

  • Thread starter Thread starter physics-dummy
  • Start date Start date
  • Tags Tags
    Formulas
AI Thread Summary
To calculate weight on a circular track, Newton's law of gravitation is essential for determining weight in Newtons, especially for an object on an asteroid. For the Porsche moving at a steady speed, centripetal acceleration can be used to find velocity without needing mass, using the formula a = v²/r. The conversion from meters per second to kilometers per hour involves multiplying by 3.6, as 1 m/s equals 3.6 km/hr. Proper unit management is crucial in these calculations to avoid confusion. Understanding these principles aids in solving similar physics problems effectively.
physics-dummy
Messages
3
Reaction score
0

Homework Statement

:

#1. You are walking on a perfectly round asteroidwith a diameter of 40km and a mass of 10 to the 16th kg. your mass is 60kg. how much will you weigh, in Newtons?

#2 a 100 kg porshe is moving at a steady speed around a cicular track waith a 1000 m radius. The porshe's centripedal acceleration is 5 m/s squared. What is teh magnitude of its velocity?

Homework Equations





The Attempt at a Solution



I tried a=v squared/r but it doesn't include the mass so i didn't think it's right and I've looked through all my notes and can't find a formula for the second one. For the first one I'm lost cause f=ma don't work. any help i would be grateful for, thanks.
 
Physics news on Phys.org
You are on the right track for the second one, and you don't need the mass. On the first one look up Newton's law of gravitation.
 
thank you very much. after i get 71 for the second answer how do i change it into km/hr
 
Put units on things, ok? If you got 71m/sec and you really want to convert to km/hr, then 1m=km/1000 and 1sec=hr/3600. Now what? Units are your friends, they help you from being confused.
 
Thanks for the help.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top