Calculating Work and Distance for a Braking Automobile

AI Thread Summary
To calculate the stopping distance of a 2200 kg automobile moving at 32 m/s with a braking force of 6000 N, the relevant kinematic equations and Newton's second law (F=ma) are applied. The braking force results in a deceleration that can be determined by dividing the force by the mass of the vehicle. The distance traveled during braking can then be calculated using the initial velocity, final velocity, and the deceleration. Additionally, the work done by the car during this time can be found by multiplying the braking force by the distance traveled. Understanding the role of friction in this scenario is also essential for accurate calculations.
grade 11 kid
Messages
1
Reaction score
0

Homework Statement


an autombile 2200kg moves with a velocity of 32m/s on a level road.
a comstant braking force of 6000N is applied to the automobile wheels bringing it to a stop eventually
a) what distance will the vehicle travel after the brake are applied?
b) calcutate the work done by the car during this time?
need to find the answer
thanks



Homework Equations


F=ma



The Attempt at a Solution



 
Physics news on Phys.org
What kinematics equations do you have?

I don't know how friction can be factored into this.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Question about car braking and tire friction
Replies
19
Views
3K
Is the Hertzian Contact Model Suitable for Simulating Car Braking on Wet Roads?
Replies
4
Views
2K
Stopping distances on a downward slope
Replies
3
Views
2K
Calculating Braking Force and Stopping Distance for an Automobile
Replies
5
Views
2K
What is the Most Effective Method for Minimum Stopping Distance in a Car?
Replies
4
Views
2K
Does Less Friction Always Mean a Shorter Braking Distance?
Replies
1
Views
1K
Calculating the Stopping distance
Replies
7
Views
3K
Kinematics car braking scenario
Replies
8
Views
3K
What is the work done by braking force on a decelerating car?
Replies
11
Views
2K
How can Superman minimize the braking distance?
Replies
21
Views
2K

Hot Threads

Recent Insights

Back
Top