Calculating Work Done on a Basketball Dropped from 5m

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The discussion focuses on calculating the work done on a basketball dropped from a height of 5 meters, which bounces back to a height of 4.3 meters. The initial calculation for the change in gravitational potential energy (ΔUg) was found to be -3.92 J, leading to a work done (W) of 3.92 J. However, it was pointed out that there was a signage error in applying the work done equation, as the formula used was for gravity rather than the work done by the ground, which is associated with non-conservative forces. The correct approach requires using a different equation to accurately determine the work done by the ground. Clarification on the correct equation is necessary for an accurate solution.
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Homework Statement


A basketball with a mass of 0.56 kg drops from a height of 5 m and bounces off the floor back up to a maximum height of 4.3 m .Find the work done on the ball by the ground during the time the ball is in contact with it.

Homework Equations


W = - Δ Ug
Ug = mgh

The Attempt at a Solution


ΔUg = mghƒ - mghι
= 0.56*10*4.3 - 0.56*10*5 = - 3.92 J
W= - Ug = 3.92 J
Can somebody check my answer please ?
Thanks for your help.
 
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The magnitude of the work done by the ground is correct, however you have a signage error because you incorrectly applied the equation for work done by the ground. The formula you used is for the work done by gravity. What equation should you be using for work done by the ground, which is work done by a non conservative force?
 

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