Calculating Work, Force, and Power in Bob's Rock Throw

AI Thread Summary
Bob throws a 620g rock at a speed of 30m/s and moves his hand forward 0.8m. To calculate the work done on the rock, the work-energy theorem can be applied, using the change in kinetic energy (W = ΔKE). The force exerted by Bob can be determined by rearranging the work formula (W = Fd), factoring in the acceleration needed to reach the final speed. The maximum power output can be calculated using the formula P = W/t, where the time taken for the throw can be derived from the distance and speed. Understanding these concepts is crucial for solving the problem accurately.
aligass2004
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Homework Statement



Bob can throw a 620g rock with a speed of 30m/s. He moves his hand forward .8m while doing so.
a.) How much work does Bob do on the rock?
b.) How much force, assumed to be constant, does Bob apply to the rock?
c.) What is Bob's maximum power output as he throws the rock?

Homework Equations



W = Fd
P = W/t

The Attempt at a Solution



For part a, I tried using W = Fd. I assumed F would be mg, but I think that the accelerating has to be factored in there somewhere as well. I got 4.861, but it was wrong.
 
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You're not given the acceleration of the rock, however you do know its mass and its final speed so to speak. Assuming the rock accelerates from rest, we can use the work-energy theorem to find the work done on the rock. So we have:

W_{TOT} = \Delta KE

Does that help?
 
I know that for K, I would substitute 1/2m(v^2), but I don't know how to find E.
 
aligass2004 said:
I know that for K, I would substitute 1/2m(v^2), but I don't know how to find E.

I'm not sure what you mean by "E." You're asked to find work, force, and power. What are you stuck on exactly?
 
Oh, oh...KE meant change in kinetic energy. I thought it meant kinetic energy times energy...I don't know why I thought that though.
 
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