Calculating Work Needed to Compress Spring

  • Thread starter Thread starter Chandasouk
  • Start date Start date
  • Tags Tags
    Spring
AI Thread Summary
To calculate the work needed to compress a spring, the user starts with the known work of 11.3 J for a stretch of 2.96 cm and seeks to find the work for a compression of 4.01 cm. They apply the formula Us = 1/2KΔX², converting distances to meters and attempting to derive the spring constant k. After calculating k as 25794 N/m, they express concern over its high value, suggesting a possible error in their calculations. Ultimately, they compute the work for the 4.01 cm compression as 20.7 J, indicating that more energy is required for greater compression. The discussion highlights the importance of correctly applying the spring work formula and understanding the relationship between distance and work.
Chandasouk
Messages
163
Reaction score
0

Homework Statement


To stretch a spring a distance 2.96 cm from its unstretched length, an amount of work of 11.3 J must be done.

How much work must be done to compress this spring a distance 4.01 cm from its unstretched length?

I did this but am not sure if it is correct.

Us = 1/2K\DeltaX2

2.96cm = .0296m

4.01cm = .0401m

\DeltaX = .0105m

What do I do from here? Would Us = 11.3J?
 
Physics news on Phys.org
Using known amount of work done, using relevant equation, find the spring constant k.
Using this value of k, find the work done in the second case.
 
With the equation U_{s}=\frac{1}{2}kx^2, you know all but one value, k. Find out what it is. Then for the second part, you'll have all values except U_{s}. which you can solve for.
 
11.3J = 1/2K(.0296m)2

K=25794 N/m but that is an insanely high number, so I do not think that is correct.

Regardless

<br /> U_{s}=\frac{1}{2}kx^2<br />

Us = 1/2(25794 N/m)(.0105m)2

=1.42 J ?
 
For the second part, x is from the unstretched length. So x = 4.01 cm.
 
I think that 1.42j is wrong.If you think that in order to move 2.96 you need 11.3j energy.So in order to move it more you would need more energy.
 
That's an way to understand that there is a error.I hope i helped
 
Us = 1/2(25794 N/m)(.0401m)2

=20.7J ?
 
Back
Top