Calculating Yield of CuSO4 Crystals from Reaction of H2SO4 and CUO

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The discussion focuses on calculating the yield of CuSO4 crystals from the reaction of H2SO4 and CuO. Participants debate whether to use CuSO4 or CuSO4.5H2O for theoretical yield calculations, with a consensus leaning towards CuSO4.5H2O due to its crystalline nature. They emphasize balancing the reaction equation correctly, suggesting that water should be included in the balance since the reaction occurs in solution. The correct balanced equations are discussed, with participants correcting each other's attempts and clarifying when to use the molar mass of CuSO4 versus CuSO4.5H2O. The conversation highlights the importance of proper stoichiometry in yield calculations.
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I was tasked to calculate the yield of CuSO4 by the reaction of H2SO4 and CUO.
My equation says the it should get CUSO4 and H2O.

But should we use CUSO4.5H2O for theoretical yield instead since it is a crystal that we are calculating - if so then I could not balance the equation...

what should I use...

many thanks
 
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CuSO4.5HsO.
 
matthew77ask said:
what should I use...

CuSO4.5H2O.
 
Hi,

Logically CuSO4.5H2O., but

If I use
CuSO4.5H2O
then what to display in the equation ?

and how to balance it? or just balance without 5H20?
[why?]
 
Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.
 
Borek said:
Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.

5CuO + 5H2SO4 --> 5CuSO4 + 5H2O

CuSO4 + 5H2O --> CuSO4.5H2O

5CuO + 5H2O --> CuSO4.5H2O

correct?

thanks.
 
Coefficients should be lowest possible - so the first one is wrong.

Second is OK.

Third is not balanced, which is obvious at first sight - there is no sulfur on the left.
 
Opps!
I am trying to combine the two equations:

5CuO + 5H2SO4 --> 5CuSO4 + 5H2O

CuSO4 + 5H2O --> CuSO4.5H2O
Adding them

5CuSO4 + 5H2O --> CuSO4.5H2O

correct?

thanks.
 
Also, when we use CuSO4 for reaction calculations, when we use Mr(CuSO4) and when do we use Mr(CuSO4.5H20) ?

seems that all CuSO4 are blue - containing the 5H2O

Many thanks...
 
Last edited:
  • #10
Try with

CuO + H2SO4 + H2O ->
 

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