Calculation and Uniqueness of Smith Normal Forms

jj4
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FYI this is a homework problem which I already have the answer to but would like to clarify some points on.

Homework Statement



Find the Smith Normal Form of the matrix

<br /> \left[ \begin{array}{cccc} 6 &amp; 0 &amp; 4 \\ 0 &amp; 6 &amp; 8 \\ 0 &amp; 3 &amp; 0 \end{array} \right]<br />

over the ring of integers.

Homework Equations



As I understand it Smith Normal Forms are unique up to multiplication by a unit in R.

The Attempt at a Solution



I have performed a series of elementary row and column operations to get to the following Smith Normal Form:

<br /> \left[ \begin{array}{cccc} 6 &amp; 0 &amp; 0 \\ 0 &amp; 6 &amp; 0 \\ 0 &amp; 0 &amp; -24 \end{array} \right]<br />

However the "answer" given is actually:

<br /> \left[ \begin{array}{cccc} 1 &amp; 0 &amp; 0 \\ 0 &amp; 6 &amp; 0 \\ 0 &amp; 0 &amp; -24 \end{array} \right]<br />

The only units in the ring are 1 and -1 so the answers are not equivalent and presumably I have gone wrong somewhere. Can someone help me out here. My problem is not only related to this example, I have the same issue with others. Is it because my Smith Normal Form and the original matrix are not actually equivalent?
 
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I'm just looking for a basic explanation of how to calculate Smith Normal Forms. Is this thread in the correct sub-forum?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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