(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Electrical Immersion heater unit

Needs to heat 10,000 litres of water from 24 Degrees C to 30 Degrees C in 24 hours

Heater is connected to 240 V.

Specific heat of the water 4.19 kJ kg-1 °C-1 and the energy gained by water is calculated from the formula Q=mc(Delta)T.

What is the current requirement of the heater (ignore energy losses from the water while heating?

2. Relevant equations

3. The attempt at a solution

My attempt

Energy gained = (10,000)(4.19)(30-24)

Energy gained = 251,400 J

Next P = w/t

251,400 J/ 86400 sec (24hours)

P = 2.9 Watts

Next I = P/V

I = 2.9 / 240

I = 0.012 A

Can you please confirm my understanding.

Many thanks Petra d.

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# Calculation Electrical Energy

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