1. The problem statement, all variables and given/known data Electrical Immersion heater unit Needs to heat 10,000 litres of water from 24 Degrees C to 30 Degrees C in 24 hours Heater is connected to 240 V. Specific heat of the water 4.19 kJ kg-1 °C-1 and the energy gained by water is calculated from the formula Q=mc(Delta)T. What is the current requirement of the heater (ignore energy losses from the water while heating? 2. Relevant equations 3. The attempt at a solution My attempt Energy gained = (10,000)(4.19)(30-24) Energy gained = 251,400 J Next P = w/t 251,400 J/ 86400 sec (24hours) P = 2.9 Watts Next I = P/V I = 2.9 / 240 I = 0.012 A Can you please confirm my understanding. Many thanks Petra d.