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zebra1707
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Homework Statement
Electrical Immersion heater unit
Needs to heat 10,000 litres of water from 24 Degrees C to 30 Degrees C in 24 hours
Heater is connected to 240 V.
Specific heat of the water 4.19 kJ kg-1 °C-1 and the energy gained by water is calculated from the formula Q=mc(Delta)T.
What is the current requirement of the heater (ignore energy losses from the water while heating?
Homework Equations
The Attempt at a Solution
My attempt
Energy gained = (10,000)(4.19)(30-24)
Energy gained = 251,400 J
Next P = w/t
251,400 J/ 86400 sec (24hours)
P = 2.9 Watts
Next I = P/V
I = 2.9 / 240
I = 0.012 A
Can you please confirm my understanding.
Many thanks Petra d.