Calculation of Workdone and Energy Answer for First and Second Question

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The discussion focuses on the calculation of work done and energy for two physics questions. For the first question, the calculations indicate that the correct answer is B, as the work done is zero due to no friction. In the second question, the work done is calculated as 280J, leading to the answer A. Participants express concerns about the poor wording of the questions, particularly regarding the assumptions made about forces and energy. Overall, the consensus is that the questions lack clarity and sufficient information for accurate answers.
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Screen Shot 2015-09-25 at 1.46.45 AM.png

Answer stated is D

Screen Shot 2015-09-25 at 1.46.28 AM.png

Answer stated is D
My attempt at the solution:


For the first question,
the calculations are as follow:

A. P=I2R = 42×12 = 192 J/s -- Missing information
B. Energy = 1/2 mv2 = 15×9= 135J
C. Energy = mgh = 10×10×1 = 100J
D. Work done = 0J ; moving against zero friction.

My answer will therefore B for the first question.

For the second question,
Work done = Ffric × d = 70N×4m = 280J

The information with regards to the mass of the object is irrelevant since the friction coefficient is not stated and the frictional force has been stated in the problem.

My answer is A for the second question.
 
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I like your answers. It appears that the wrong answer D in each case arises from the mistaken view that work must be done against the force of gravity and that this work is equal to the weight times the distance moved (even though the weight force is perpendicular to the displacement).

The wording of the questions is not very good. In option D for #14 and in #25, there is no information about whether or not the speed of the object remains constant . In #25 the phrase "energy exerted" is a bit odd. We don't normally think of "exerting" energy.
 
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TSny said:
I like your answers. It appears that the wrong answer D in each case arises from the mistaken view that work must be done against the force of gravity and that this work is equal to the weight times the distance moved (even though the weight force is perpendicular to the displacement).

The wording of the questions is not very good. In option D for #14 and in #25, there is no information about whether or not the speed of the object remains constant . In #25 the phrase "energy exerted" is a bit odd. We don't normally think of "exerting" energy.

Thanks for your prompt reply and assurance that my conceptual knowledge is not at risk. May also I get you to acknowledge if the information provided for #14 (A) is incomplete to deduce the energy consumed.
 
You are completely right. You would also need to be given a time period in order to get energy in #14 (A).
 
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I agree. As written the answers are B and A. Very badly worded questions.
 
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