- #1
khdani
- 55
- 0
i know that the maximal growth is the gradiend of a function.
the formula is:
[tex]
\triangledown f=f_x'\vec{i}+f_y'\vec{j}+f_z'\vec{k}
[/tex]
so when i am given a function
[tex]f(x,y,2x^2+y^2)=3x-5y[/tex]
i am was told that it growth on point M(1,2,6) in direction
[tex]\hat{a}=(\frac{1}{3},\frac{2}{3},\frac{2}{3})[/tex] is 1
what is the gradient of f (maximal growth).
i tried to get it like this:
first of all i need a function which looks like this f(x,y,z)=...
in order to find the gradient
i don't know how to do the gradient of a function which i was given.
if i substiute the point
f(1,2,6)=3-10=7
i know i should write
[tex]
(grad f(1,2,6)\dot \hat{a}=1
[/tex]
?
the formula is:
[tex]
\triangledown f=f_x'\vec{i}+f_y'\vec{j}+f_z'\vec{k}
[/tex]
so when i am given a function
[tex]f(x,y,2x^2+y^2)=3x-5y[/tex]
i am was told that it growth on point M(1,2,6) in direction
[tex]\hat{a}=(\frac{1}{3},\frac{2}{3},\frac{2}{3})[/tex] is 1
what is the gradient of f (maximal growth).
i tried to get it like this:
first of all i need a function which looks like this f(x,y,z)=...
in order to find the gradient
i don't know how to do the gradient of a function which i was given.
if i substiute the point
f(1,2,6)=3-10=7
i know i should write
[tex]
(grad f(1,2,6)\dot \hat{a}=1
[/tex]
?