Calculus derivation with radicals

JerG90
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Homework Statement



godcalc.jpg


Homework Equations



Basic rules- Power, product, and quotient

The Attempt at a Solution



The first step would be to rewrite the equation:

f(x)= x^2/3 + 1/ x^1/2

I'm lost here. I don't know what to do when the variable is in the denominator like that.

Any help would be greatly appreciated.
 
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JerG90 said:

Homework Statement



godcalc.jpg


Homework Equations



Basic rules- Power, product, and quotient

The Attempt at a Solution



The first step would be to rewrite the equation:

f(x)= x^2/3 + 1/ x^1/2

I'm lost here. I don't know what to do when the variable is in the denominator like that.

Any help would be greatly appreciated.

You can bring the denominator up, and 1/x^(1/2) becomes x^(-1/2)... or you can use the quotient rule for derivatives.
 
rememeber x^{\frac{-1}{2}}=\frac{1}{x^{\frac{1}{2}}}
also recalll the formula for derivative of x^{n}
 
Or as you suggested, for your problem with the second part, just use the quotient rule!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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