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## Homework Statement

Hi,

I'm really struggling with trying to come up with the error bound when doing taylor series problems

Use the reaminder term to estimate the absolute error in approximating the following quantitites with the nth-order Taylor Polynomial cnetered at 0. Estimates are not unique.

e^.25; n=4

## Homework Equations

If n is a fixed integer, suppose there exists a number M such that |f^(n+1)(c)|<=M for all c between a and x inclusive. The remainder in nth-order Taylor polynomial for f centered at a satisfies

|Rn(x)|=|f(x)-Pn(x)|<= M*|x-a|^(n+1)/(n+1)!

## The Attempt at a Solution

So apparently if we let f(x)=e^x, then f^(5)(x) = e^x, which I agree with fully

But I don't see how e^.25 is bounded by 2 and this is what we set M equal to. e^.25 is about 1.284025417...

I understood the previous similar problem that I did with sin(.3); n=4, because the nth derivative of sin(x) is either +/- sin(x) or +/- cos(x) which will always be <= 1 so this makes sense to use for a value of M, M=1 in this problem...

but for the one that I'm stuck on I don't see why we set M=2. The nth derivative of e^x is always going to be e^x which doesn't have a max value and increases without bound...

I hope it makes sense as to were I'm getting confused. Thanks for any help.