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1) The problem.
Determine the coordinates of the points on the graph of f(x) = (x^3 - 3x^2)^2 at which the graph is tangent to the x-axis.
2) Relevant Equations
Chain Rule of Derivatives ?
3) My attempt.
I used chain rule to get f'(x) = (2)(x^3 - 3x^2)(3x^2 - 6x
I don't know where to go from here what does it mean by the graph is tangent to the x-axis?
Determine the coordinates of the points on the graph of f(x) = (x^3 - 3x^2)^2 at which the graph is tangent to the x-axis.
2) Relevant Equations
Chain Rule of Derivatives ?
3) My attempt.
I used chain rule to get f'(x) = (2)(x^3 - 3x^2)(3x^2 - 6x
I don't know where to go from here what does it mean by the graph is tangent to the x-axis?