# Calorie to Heat Conversion: Cheese Food Experiment

• jaedonsmami23
In summary, the conversation discusses the process of testing the nutrition label on a package of processed cheese food. The label indicates that a 20.0 g serving has 175 Calories. To test this, a small piece of cheese is burned under a can with 100.0 mL of water. It is found that 1.0 gram of cheese was burned to heat the water. Assuming all the heat released by the cheese was absorbed by the water, the question is posed about the change in temperature of the water at the end of the experiment. The solution to this problem involves determining the amount of heat released per gram of cheese burnt.
jaedonsmami23
The nutrition label on a package of processed cheese food indicates that a 20.0 g serving has 175 Calories. To test this you put a small piece of cheese under a can with 100.0 mL of water and burn the cheese. You find that 1.0 grams of cheese was burned to heat the water. Assume that all of the heat released by the cheese was absorbed by the water(let's pretend), what is the change in temperature of the water at the end of the experiment?

Please read the Rules (tab at top of the page). You must share your attempt at a solution, and indicate where you are having troubles.

I don't even know where to begin

Ok. How many calories of heat are released per gram of cheese burnt?

Based on the information provided, we can calculate the amount of heat released by the 1.0 gram of cheese burned. Using the conversion factor of 1 gram of cheese = 175 Calories, we can determine that 1.0 gram of cheese releases 175/20.0 = 8.75 Calories of heat.

Next, we need to calculate the amount of heat needed to raise the temperature of 100.0 mL of water by 1 degree Celsius, also known as the specific heat capacity of water. This value is 4.18 Joules/g°C.

Using the formula Q = mCΔT, where Q is the heat released, m is the mass of the water, C is the specific heat capacity, and ΔT is the change in temperature, we can solve for ΔT.

Plugging in the values, we get:

8.75 Calories = 100.0 g x 4.18 J/g°C x ΔT

ΔT = 8.75 Calories / (100.0 g x 4.18 J/g°C) = 0.0209°C

Therefore, the change in temperature of the water at the end of the experiment is approximately 0.0209°C. This small change in temperature is not significant and may not be detectable by most thermometers. It is important to note that this experiment is a simplified model and does not take into account other factors such as heat loss to the surrounding environment.

## 1. How do you measure the calorie content of cheese?

The calorie content of cheese can be measured by using a calorimeter, which is a device that measures the amount of heat released when a food is burned. This heat is then converted into calories using a conversion factor.

## 2. Can the calorie content of cheese vary between different types?

Yes, the calorie content of cheese can vary between different types as it depends on the type of milk used, the fat content, and the aging process. For example, a serving of cheddar cheese will have a different calorie content than a serving of mozzarella cheese.

## 3. How does the cheese food experiment work?

The cheese food experiment involves burning a sample of cheese in a calorimeter and measuring the amount of heat released. This heat is then converted into calories using a conversion factor. The experiment is repeated multiple times to ensure accurate results.

## 4. Why is it important to know the calorie to heat conversion of cheese?

Knowing the calorie to heat conversion of cheese is important for understanding the energy content of the food and how it can impact our bodies. It can also help with portion control and making informed dietary choices.

## 5. Can this experiment be done at home?

Yes, this experiment can be done at home with the proper equipment and safety precautions. However, for accurate results, it is recommended to conduct the experiment in a controlled laboratory setting.

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