Can a Mattress Spring Increase Tennis Ball Launcher Velocity?

AI Thread Summary
The discussion focuses on building a tennis ball launcher that utilizes stored mechanical energy, similar to a mortar or cannon. The participants have experimented with various commercial springs but are struggling to achieve sufficient velocity for the tennis ball to exit the barrel. They are considering using a mattress spring and seek suggestions to enhance the launch velocity. Key considerations include reducing friction, decreasing mass, increasing the spring constant, and ensuring the ball fits properly within the tube to avoid air pressure issues. Overall, optimizing these factors is crucial for improving the launcher’s performance.
bkamer
Messages
1
Reaction score
0
Me and two friends need to build a tennis ball launcher using nothing but stored mechanical energy to propel it. Our concept is similar to a mortar or cannon. We tried some comercial springs from Home Depot and even a spring from inside a sprinkler head, but the tennis ball does not have enough velocity to even get out of the barrel. We are considering using a mattress spring, but need some ideas on how to increase the velocity. Any suggestions are welcome. Thanks in advance.
 
Physics news on Phys.org
Think about reducing friction. If that doesn't help too much, the only options using a spring would be to reduce mass, increase spring constant, or compress the spring more. As you most likely know, this is due to:
F_{net}=ma and
F_{spring}=-kx
 
Last edited:
Is the spring end of tube open?
If not and the ball fits snugly in the tube, you have problems with air pressure.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...

Similar threads

Back
Top