Can Ampere's Law Still Apply When Whole Solenoid Is Enclosed?

AI Thread Summary
Ampere's Law can still be applied to a rectangle enclosing a whole solenoid because it depends on the total current enclosed by the Amperian surface. When the rectangle encloses the entire solenoid, the magnetic field outside is ideally zero, leading to integrals of the sides being zero. However, since the current enclosed is non-zero, it contributes to the magnetic field inside the solenoid, allowing the law to hold true. The confusion arises from the cancellation of currents on opposite sides of the rectangle, but the net enclosed current is what matters. Thus, Ampere's Law remains valid as long as the total current is considered, regardless of the rectangle's orientation.
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Homework Statement


I want to know why Ampere's Law can sitll be applied/valid if the Amperian surface is drawn as a rectangle which encloses a whole solenoid. Normally the rectangle would just include one side of the solenoid.


Homework Equations





The Attempt at a Solution



When only one side of the solenoid is enclosed, Ampere's Law will work because B and ds will be parallel on the side of the rectangle which is inside the solenoid so we can intergrate this to an non-zero value. But I'm confused about when the whole solenoid is enclosed by the rectangle. It is an ideal solenoid so there should be no magnetic field outside the solenoid so the integral of the 2 sides which are parallel to B will be 0. The other two sides are perpendicular to B so they will also = 0. The only reason I can think that Ampere's Law still applies is that all of the current is enclosed so that somehow helps with the solution?

I'm really stuck here, because I keep getting the left side of the equation =0 so I cannot see how the law is still valid.
 
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Remember that current has a direction. You have to consider not only how much current goes through the rectangle, but in which direction it goes through.
 
But I thought it only depended on the direction of B and ds for the left side of the laW?
 
So the current travels in opposite directions on opposite sides of the rectangle and therefore the current will cancel out? So when we evaluate each side of the rectangle with the intergral involving B and ds we are supposed to get 0 because the right side of the equation is also supposed to equal zero?
 
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