Can an Adiabatic Process be Isothermal?

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An adiabatic process, by definition, cannot be isothermal because it involves no heat transfer (dQ = 0), leading to a change in temperature. The discussion highlights a problem involving a cycle with various processes, where the adiabatic leg shows no temperature change, which is incorrect. The user Daniel is confused about the temperatures at points B and C in his cycle, both calculated as 2.44x10^4 K. He plans to create a new thread to further explore this issue, indicating that it requires more detailed analysis. The key takeaway is that an adiabatic process cannot simultaneously be isothermal.
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In an adiabatic process, I know that that dQ is zero. I am doing a problem with a cycle that has different types of processes, and when I get to the adiabatic leg, I am finding that the change in temperature is zero. Therefore, the work done and the change in internal energy also equal zero.

Is this possible? Can an adiabatic process also have no change in temperature, therefore being isothermal?
 
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OK, so in the problem A->B is isobaric, B->C is adiabatic, C->D is isothermal, D->A is isochoric.

Pa = 2atm, Va = 2 m^3, n = 1mole, Vb = 1/2Va, Pa = 2Pd

I always end up with the temperatures of B and C both equaling 2.44x10^4 K. What am I doing wrong?
 
I'm going to make a new post of this since it's really no longer a "small question."
 
How come you end up with equal temp.?Post your work.

Daniel.
 
I posted my work in a new thread since it is not a small problem anymore.
 
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