Can antimatter annihilation lift 81 million tons half a mile into the air?

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The discussion centers on calculating the mass that can be lifted using the energy from antimatter annihilation. The initial attempt involved using Einstein's equation E=mc^2 with 4 grams of antimatter, leading to an incorrect mass lift estimate. A correction was proposed, suggesting that the total energy should account for both matter and antimatter, effectively doubling the mass in the energy calculation. The correct approach involves using the potential energy formula, which confirms that just 4 grams of antimatter can theoretically lift 81 million tons over half a mile. This highlights the immense energy potential of antimatter.
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Hey all,

Homework Statement



"Suppose that we could use the energy released
when 4 g of antimatter annihilates 4 g of
matter to lift a mass 1 km from the Earth’s
surface.
How much mass could we lift? Answer in
units of kg."

Homework Equations



e=mc^2
w=fd
f=ma

The Attempt at a Solution

I was attempting to find the energy with e=mc^2 and using .004kg as the mass. Then I tried using work(energy)=force*distance and force=mass*acceleration (using gravitational potential energy) but my answer was incorrect. For the record, i answered 3.67e10 kg but no luck. I'm stumped. :(

EDIT: I think the proper way is using the potential energy equation [energy=mass*gravity*height] after I have found energy from [e=mass*speed of light^2] Is this right?

Would the total energy released be from .004kg or from .008kg of matter?
 
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I'll take a stab at it. According to http://en.wikipedia.org/wiki/Antimatter_weapon the amount of energy produced by a gram of antimatter is 180 Tjoules, which is twice the amount predicted by your method. It may be since both matter and antimatter are being destroyed you must double the mass in E=mc2. Perhaps if you doubled your answer?
 
krausr79 said:
I'll take a stab at it. According to http://en.wikipedia.org/wiki/Antimatter_weapon the amount of energy produced by a gram of antimatter is 180 Tjoules, which is twice the amount predicted by your method. It may be since both matter and antimatter are being destroyed you must double the mass in E=mc2. Perhaps if you doubled your answer?

Let me see if that works..
 
wohooo that's it! thanks a bunch

Interesting to note that just 4 grams of anti matter (like the weight of a pen) can move 81 million tons of *whatever* more than half a mile vertically.
 
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