I Can Antiparticles Collide with Each Other and Create Energy?

gabi123
Messages
3
Reaction score
0
Now it is common knowledge that antiparticles destroy particles on collision, and release the same amount of energy as if the masses of the two particles were combined and plugged into E=mc^2. But what about an antiparticle colliding with another antiparticle? Would they have the same effect on collision, or would they bounce off of each other like two normal particles?
 
Physics news on Phys.org
The collision of two anti-particles would be just as the collision of two normal particles.
 
  • Like
Likes mfb
1. the collision of two "normal" particles doesn't necessarily result to them bouncing off... it's way more interesting than that (eg the collision of quarks in protons at LHC).
2. If an antiparticle collided with an antiparticle you could get similar results as for particles (as Orodruin said).
 
  • Like
Likes mfb
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top