Can anyone explain why this happens? mechanics

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The experiment involves dropping a mass onto a pencil balanced on the edge of a table, resulting in an unexpected backward jump instead of the usual forward rotation. Key factors influencing this behavior include the point of impact on the pencil, the distribution of weight, and the moments created at the edge of the table. The mass may slide off the sharpened end before delivering full force, preventing a complete revolution. As the fraction of the pencil hanging off the table decreases, the likelihood of a backward jump increases. This phenomenon is explained through principles of torque and Newton's laws of motion.
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Ok this is an experimental result that has stumped me (I posted a while ago on the same topic but received no replies so this is a more specific question.)

This picture shows what happens:

l_4794ebf3f2dd33702a44d8f91e16de7a.jpg


The experiment involves dropping a mass (through a tube, visible in the top right of each shot) onto a pencil that is balanced on the edge of the table. The picture is video print-outs.. I realize the picture quality isn't great but basically, in this case the pencil jumped up backwards instead of the usual forwards (clockwise from this direction) rotation and movement.

So yeah, if anyone can explain WHY or give me some clues on how to start that would be great! Thanks.
 
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hmm if the pencil was sharpened, it's possible that the mass hit it on the cone part, making the mass "slide off" before it delivered all of its force. That would explain why the pencil did not complete a revolution. It's also possible that the eraser (i assume that's what it is on the left side of the pencil) was a large enough source of clockwise torque to prevent the pencil from flipping forward.
 
I would think shape of objects is not important, force, angle, and motion can be like actions and reactions on a pool table.
 
Weight of the pencil act at the center of the pencil. When the mass hits the pencil, the reaction at the edge of the table produces an anticlockwise moment which is greater than the clockwise moment due to weight of the pencil.It is the cause of the backward jump of the pencil. If you perform the same expefriment with a heavy lead rod of the same shape, you may no get the same result.
 
Hi Zoe-b,

In your earlier post you had said that this backward flipping happens when only a small fraction of the whole length is sticking out. Is that always true? Also, in that case, at which point on the pencil is the ball dropping on?
 
Hey, thanks for the replies!
hmm if the pencil was sharpened, it's possible that the mass hit it on the cone part, making the mass "slide off" before it delivered all of its force. That would explain why the pencil did not complete a revolution. It's also possible that the eraser (i assume that's what it is on the left side of the pencil) was a large enough source of clockwise torque to prevent the pencil from flipping forward.
No, sorry I didn't explain very well, but the pencil was the other way round, with the sharpened bit on the table. It doesn't have an eraser, the red-ish thing you can see is coloured paper wrapped round with sellotape; I used different colours in the centre and on each end in order to make my videos clearer- I got the same effect before adding the paper.

Weight of the pencil act at the center of the pencil. When the mass hits the pencil, the reaction at the edge of the table produces an anticlockwise moment which is greater than the clockwise moment due to weight of the pencil.It is the cause of the backward jump of the pencil. If you perform the same expefriment with a heavy lead rod of the same shape, you may no get the same result.
Not quite.. it's probably not obvious from the pictures but the direction of rotation is actually always clockwise. In the above film, the pencil spins forwards but moves backwards.

In your earlier post you had said that this backward flipping happens when only a small fraction of the whole length is sticking out. Is that always true? Also, in that case, at which point on the pencil is the ball dropping on?
Yeah, as far as I can tell it is. As the fraction sticking out decreases, the pencil is more likely to go upwards, and eventually, backwards. The current theory I have (gained from talking to my teacher) is that the weight hits the very end of the pencil and therefore tilts when hitting the pencil. It moves forwards, and by Newtons 2nd (? hehe) law the pencil therefore moves backwards. Consider a metre ruler with a few centimetres hanging off the edge of the table... there's no way it'll spin forwards, and if you hit it right on the end it jumps backwards. This effect is similar but magnified because the pencil is lighter...

I think!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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