Can anyone help me slove this question?

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To calculate the terminal speed of a bacterium in water, the drag force equation F drag = −Crv is used, with parameters including a mass of 4 x 10^-15 kg, a drag coefficient of 0.02 N•s/m², and a radius of 1 μm. A force diagram is necessary to determine if the bacterium is in equilibrium, which it is at terminal velocity when the drag force equals the weight. The speed can be calculated using the drag force equation, leading to a specific terminal velocity value. Additionally, the time taken for the bacterium to fall 2.5 m can be derived from this speed. The discussion emphasizes the importance of showing work for effective assistance in solving the problem.
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Calculate the terminal speed for a bacterium in water. Use the expression for the drag force in the equation
F drag = −Crv .
Assume the bacterium has a mass m = 4 10−15 kg, a drag coefficient
C = 0.02 N • s/m2 and can be approximated as a sphere of radius r = 1 μm.
a. Draw a force diagram for the bacterium. Is it in equilibrium? Why?
b.Find the speed (size of the velocity) of the bacterium
c.How long does it take a bacterium to fall from the top of a lake of depth 2.5 m to the bottom if it falls at this speed?
 
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