smoothoperator said:
Shouldn't the different clock rate imply different simultaneity?
No, because simultaneity is a convention, not a physical thing. It's simply a matter of which events the different observers, with their different clocks, agree to say happened "at the same time". That's not the same thing as saying how much time elapsed between two events which are not at the same time.
Here's a concrete example for the rotating disc. Suppose the observer O, at the center of the disc, is emitting light pulses in a particular direction--say towards a particular distant object such as a star. Say the radius of the disc is 10 feet, so it takes light 10 nanoseconds, according to the center clock, to go from the center of the disc to the edge. We also have a particular observer D, at the edge of the disc, who is passing the radial line along which the light pulses travel at particular instants of interest. This observer takes, let us say, 1 second to complete a revolution, according to observer O (i.e., by observer O's clock, the disc revolves once per second).
Now consider the following events:
A: Observer O emits light pulse #0.
A1: The event on observer D's worldline that is simultaneous with A, according to the center observer.
B: Light pulse #0 reaches the edge of the disc. At the same instant, observer D is passing the radial line along which the light is traveling, so light pulse #0 passes him at this instant.
B1: The event on observer O's worldline that is simultaneous with B, according to the center observer.
C: The center observer emits light pulse #1.
C1: The event on observer D's worldline that is simultaneous with C, according to the center observer.
D: Light pulse #1 reaches the edge of the disc. At the same instant, observer D has made one revolution and is again passing the same radial line, so light pulse #1 passes him at this instant.
D1: The event on observer O's worldline that is simultaneous with B, according to the center observer.
Now, observer D adopting observer O's simultaneity convention just means that observer D agrees to say that events A and A1, B and B1, C and C1, and D and D1, each happen at the same time. It does
not mean that observer D has to agree that 10 nanoseconds elapse between A/A1 and B/B1, or between C/C1 and D/D1. Observer D can still say that, by his clock, less than 10 nanoseconds elapse between those pairs of events; i.e., his clock can still tick slower than observer O's clock. It also does not mean that observer D has to agree that 1 second elapses between B/B1 and D/D1; he can still say that, by his clock, less than 1 second elapses between those pairs of events (i.e., that by his clock, the disc takes less than 1 second to complete a revolution). All observer D has to agree to is which pairs of events are simultaneous.
Obviously, the coordinate chart observer D is implicitly using, if he agrees on simultaneity with observer O but uses a different tick rate for time, is not an inertial chart. But there's nothing that requires him to use an inertial chart. Nothing changes, physically, about anything in this scenario if he adopts the non-inertial chart being described. All that changes is how he labels events with coordinates.
smoothoperator said:
If according to the centre clock clocks A and B are simultaneous and tick slower than the proper time rate of the centre clock, if we adopt the centre clock convention, at which rate would the centre clock tick wrt to clocks A and B?
Faster. See above.