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Inequalities of negative arguments in complex numbers

  1. Dec 15, 2015 #1
    1. The problem statement, all variables and given/known data
    Arg z≤ -π /4

    2. Relevant equations


    3. The attempt at a solution
    I'm confused whether the answer to that would be more than -45° or less. Should the approach to arguments be the same as in negative numbers?
     
  2. jcsd
  3. Dec 15, 2015 #2

    SammyS

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    The problem is the same whether stated in degrees or in radians.

    Yes, the approach is the same as for negative numbers.

    Regardless of the signs of two numbers, a < b means that b - a is positive.
     
  4. Dec 15, 2015 #3
    Thanks! To confirm, the answer would be 60°...etc?
     
  5. Dec 15, 2015 #4

    Mark44

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    ???
    60° is a positive angle. Do you know how to convert from radians to degrees? Your answer above suggests that you don't.
    The answer would not be a single number. It would be an interval of numbers, all of which are less than ##-\pi/4##.
     
  6. Dec 15, 2015 #5

    SammyS

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    Is it true that 60° ≤ -45° ?
     
  7. Dec 15, 2015 #6
    Maybe you are confused with the fact that the argument is defined modulo two pi ?
     
  8. Dec 15, 2015 #7

    Ray Vickson

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    You need to decide whether you are taking ##\arg \, z ## in ##[0, 2\pi]## in ##[-\pi, \pi]##.
     
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