Can I Add Sine and Cosine Functions with a Non-Factorable Scalar?

  • Thread starter Thread starter mutzy188
  • Start date Start date
  • Tags Tags
    Cosine Functions
AI Thread Summary
To add sine and cosine functions with non-factorable scalars, expand the cosine term using the angle addition formula. For example, in the expression 5*cos(wt) + 6*cos(wt + π/4), first expand cos(wt + π/4) into its components. After expansion, group like terms to simplify the expression. The result can be expressed in the form R*cos(wt ± A) or R*sin(wt ± A). This method allows for the combination of the functions despite the presence of scalars.
mutzy188
Messages
37
Reaction score
0

Homework Statement



Hi guys,

I don't know if this should go here because it is an excerpt from a higher level problem. The part where I get stuck is when I try to add the cosine functions.

Is there any way to add sine and cosine functions that have a scalar in front that cannot be factored out? For example:

5*cos(wt) + 6*cos(wt + pi/4)

If there weren't any numbers in front of the functions then I could use the trig identity. What can I do with the numbers there? Thanks
 
Physics news on Phys.org
5cos(wt) + 6*cos(wt + π/4)


expand out cos(wt+π/4) then group the like terms. Then you can either put in the form Rcos(wt±A) or Rsin(wt±A)
 
cos(A+ B)= cops(A)cos(B)- sin(A)sin(B).
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top