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Does l'hospitals rule work here?:

[tex]\lim_{h\to_0}\frac{f\left(8+h\right)-f\left(8\right)}{h}[/tex] for [tex]f\left(x\right)=x^\frac{4}{3}[/tex]

then i would get,

[tex]\lim_{h\to_0}\frac{f\left(8+h\right)}{1}[/tex]

then,

[tex]=\frac{\left(8\right)^\frac{4}{3}}{1}[/tex] ?

is that it?...

[tex]\lim_{h\to_0}\frac{f\left(8+h\right)-f\left(8\right)}{h}[/tex] for [tex]f\left(x\right)=x^\frac{4}{3}[/tex]

then i would get,

[tex]\lim_{h\to_0}\frac{f\left(8+h\right)}{1}[/tex]

then,

[tex]=\frac{\left(8\right)^\frac{4}{3}}{1}[/tex] ?

is that it?...

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