Can Invertible Matrices Help Prove the Invertibility of Transposes?

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Homework Statement



[PLAIN]http://uploadpie.com/fHoAj

Homework Equations





The Attempt at a Solution



[PLAIN]http://uploadpie.com/fCgEI
 
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It's easy to show that if a matrix A is invertible, then so is its transpose AT. Do you know any facts about invertible matrices that might help you do this?
 
Fredrik said:
It's easy to show that if a matrix A is invertible, then so is its transpose AT. Do you know any facts about invertible matrices that might help you do this?

Yes, it is very easy to prove that. Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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