Can Police Catch the Speeding Motorist?

  • Thread starter Thread starter aflowernamedu
  • Start date Start date
  • Tags Tags
    Information
AI Thread Summary
The discussion revolves around calculating the distance at which police can catch up to a speeding motorist. After a 2-second delay, the police accelerate for 15 seconds, covering 281.25 meters and reaching a speed of 37.5 m/s. Meanwhile, the motorist travels 510 meters in the same time frame, leaving the police 228.75 meters behind. With a relative speed of 7.5 m/s, it takes an additional 30.5 seconds for the police to catch up, totaling 47.5 seconds from the initial observation. The intersection occurs 1,187.5 meters from the observation point.
aflowernamedu
Messages
3
Reaction score
0
How would I solve this?

2 police officers are standing on a road. A motorist comes at 108km/hr(30m/s) The police take 2 s to assess the situation. Then their patrol car accelerates at 2.5m/s^2 for 15s after the 2s and then continues at uniform speed. How far from the observation point does the intersection take place? Assume the motorist maintains a constant speed of 108km/hr?
 
Physics news on Phys.org
Yes you do, assuming the question means the police react as the bike passes parallel to them.

using:

S = ut + 1/2*a*t2

You find that the police travel 281.25m in the 15 seconds they accelerate, plus the 2 seconds they waited, so in 17s they have traveled 281.25m and accelerated to a constant velocity of 37.5m/s

In this time the motorbike has traveled 17*30 = 510m so the police after 17s are a distance of 228.75m behind the bike

The relative speed between the two is 7.5m/s

So how long does it take to make up 228.75m at 7.5 m/s?

228.75 / 7.5 = 30.5s

plus the original 17s

30.5 + 17 = 47.5s until the police are level with the biker.
 
Thank you ,but I still am not sure of the answer to "how far from the observation point did the intersection take place?"
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top