Can sodium sulphate, p-toluidine, and benzoic acid form hydrogen bond

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Sodium sulphate, p-toluidine, and benzoic acid can form hydrogen bonds with water due to their molecular structures. Compounds with lone pairs on oxygen can act as hydrogen bond acceptors, while those with -OH groups can serve as donors. P-toluidine features an amine group that functions as both a donor and an acceptor, enhancing its hydrogen bonding capability. Additionally, the -OH groups in p-toluidine and benzoic acid contribute to their roles as hydrogen bond donors. Overall, these compounds fulfill the necessary requirements for hydrogen bonding with water.
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can sodium sulphate, p-toluidine, and benzoic acid form hydrogen bond with water?
 
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What are the requirements for being a hydrogen bond acceptor or donor? Do these compounds fulfill those requirements?
 


do they all have h-bonds with water because they all contain O?
 


Yes, compounds with lone pairs on an oxygen atom are capable of being hydrogen bond acceptors and can hydrogen bond with water. The compounds contain other hdyrogen bond donors and acceptors as well. The amine group on p-toluidine can act as both a hydrogen bond donor and acceptor. Also, the phenolic -OH from p-toluidine and the carboxylic acid -OH of benzoic acid can act as a hydrogen bond donor in addition to being a hydrogen bond acceptor.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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