Can someone answer this easy phsyics problem about vertical height

AI Thread Summary
A basketball player achieves a hang time of 0.978 seconds while dunking, and the problem involves calculating the vertical height attained using the acceleration of gravity at 9.8 m/s². The formula H = 0.5gt² is used, with the total time divided by two to account for the ascent and descent. Participants emphasize showing work for better assistance and clarify that the time taken to reach maximum height is half the total hang time. The discussion concludes with an explanation that the time is halved because the ascent and descent times are equal. Understanding this concept is crucial for solving similar physics problems.
Casey314stl
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Homework Statement

A basketball player achieves a hang time of 0.978 s in dunking the ball.
What vertical height will he attain? The
acceleration of gravity is 9.8 m/s^2

Answer in units of m

Homework Equations


?

The Attempt at a Solution

9.8/0.978^2= 10.245

Homework Statement


Homework Equations


The Attempt at a Solution

 
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Yes. You can.

We do not (can not) do homework for you. Show your work, we can help.
 
The attempt at a solution 9.8/0.978^2= 10.245
 
Casey314stl said:
The attempt at a solution 9.8/0.978^2= 10.245

Remember that H=.5gt^2

Retry and see what you get.
 
DaveC426913 said:
Yes. You can.

We do not (can not) do homework for you. Show your work, we can help.

I tried H=.5*g*t^2 and got 4.68677?
 
22.9653?
 
Casey314stl said:
I tried H=.5*g*t^2 and got 4.68677?

Remember that time going up = time coming down .
 
Casey314stl said:
22.9653?

No since t(up)=t(down)

then: H=.5g*(t/2)^2
 
mtayab1994 said:
Remember that time going up = time coming down .

what?
 
  • #10
mtayab1994 said:
No since t(up)=t(down)

then: H=.5g*(t/2)^2

Thanks a lot I got it but why is it half time^2?
 
  • #11
When you have the time going up = time going down, then you have: t(up)=t(down)=.978/2

I'm helping you too much.
 
  • #12
mtayab1994 said:
When you have the time going up = time going down, then you have: t(up)=t(down)=.978/2

I'm helping you too much.

I already got the the answer from the last response I was just wonder why it was half the time^2 if that was for every problem for this equation or just if an object is traveling up?
 
  • #13
Casey314stl said:
I already got the the answer from the last response I was just wonder why it was half the time^2 if that was for every problem for this equation or just if an object is traveling up?

Well since he is jumping upwards he only takes half of the time to get to his maximum height. Therefore the rest of the time is spent coming down. Hence no need for the time coming down.
 
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