Can someone check if i'm doing this right?

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SUMMARY

Dubbie is moving towards a mirror at a speed of 3.5 m/s, resulting in an image speed of 7.0 m/s relative to Dubbie, calculated using the formula v Dubbie + v mirror = v image. When Dubbie walks away from the mirror at an angle of 30 degrees, the speed of the image relative to Dubbie is determined by calculating the component of Dubbie's velocity normal to the mirror surface. The correct calculation involves using the sine function, yielding a normal velocity of 1.75 m/s, which should be doubled to find the image speed.

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Dubbie is moving directly along a normal line toward a plain mirror at a speed of 3.5 m/s, what is the speed of the image relative to Dubbie?

v Dubbie + v mirror = v image
3.5 m/s + 3.5 m/s = 7.0 m/s


What is the speed of the image, relative to Dubbie, if Dubbie walk away from the mirror surface at 3.5 m/s at an angle of 300 to the mirror surface?

Given:
θ = 300
v= 3.5 m/s

x/v= sinθ
x/(3.5 m/s) = sin300
x = [(3.5 m/s) sin300]
x = 1.75 m/s
 
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Sorry.. should be sin 30 deg
 
I'm not sure what you're doing for part 2. Have you drawn a diagram of what is happening and what you need to find out? Basically you want to find the velocity normal to the surface of the mirror and double that.
 

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