Can someone explain this example ? (Gram-schmidt Orthago

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SUMMARY

The discussion focuses on the calculation of inner products using integration in the context of the Gram-Schmidt process. Specifically, it clarifies how to compute the inner products \(\langle 1, 1 \rangle\) and \(\langle t, 1 \rangle\) using definite integrals from 0 to 1. The calculations yield \(\langle 1, 1 \rangle = 1\) and \(\langle t, 1 \rangle = \frac{1}{2}\), which serve as the denominator and numerator for the first term in the Gram-Schmidt orthogonalization process. The user seeks assistance in understanding these calculations due to discrepancies in their own results.

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http://dl.dropbox.com/u/33103477/4.png

Can someone explain to me how the bits in red are calculated with Integration, the examples are doing my head in and it would be really useful if a human could show me how they are getting the values cause mine are different.
 
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For example, the first circle is the integration of t times 1, from 0 to 1, which is equal to [itex]\frac{t^2}{2}|_0^1=\frac{1}{2}[/itex]. The rest are the same
 
Here's a bit more detail:
\begin{align*}
\langle 1, 1 \rangle &= \int_0^1 1\cdot 1 \, dt = t\big|_0^1 = 1 \\
\langle t, 1 \rangle &= \int_0^1 t\cdot 1 \, dt = \left. \frac{t^2}{2}\right|_0^1 = \frac{1}{2}
\end{align*} Those are, respectively, the denominator and numerator in the first term you circled.
 

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