Can someone help me to calculate the velocity at Stack Tip?

AI Thread Summary
To calculate the velocity at the stack tip with a larger diameter of 2.5 m, the equation V1A1 = V2A2 may not be applicable due to the compressibility of flue gases, unlike incompressible fluids. There is confusion regarding the units used in the problem, as "velocity" is incorrectly referenced in m3/s instead of m/s, which is necessary for velocity calculations. Clarification on the relationship between flow rate and velocity is needed to simplify the problem. The discussion emphasizes the importance of using the correct units and understanding the nature of the fluid involved. Accurate calculations will depend on resolving these unit discrepancies.
Suradanai
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Homework Statement


How can we calculate the velocity at stack tip if the distance of larger diameter is 2.5 m?
I think i cannot use the equation of V1A1 = V2A2 because they may have some effect from 2.5 m of distance.
Thank you very much.

Homework Equations


Q1=Q2

The Attempt at a Solution


V1A1 = V2A2
45.74*2.4 = V2*6.16
V2 = 17.82 m/s
 

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Suradanai said:

Homework Statement


How can we calculate the velocity at stack tip if the distance of larger diameter is 2.5 m?
I think i cannot use the equation of V1A1 = V2A2 because they may have some effect from 2.5 m of distance.
I think you're right. That formula applies to incompressible fluids like water. The flue gases are of course compressible.

I'm afraid I must leave this one to other helpers.
 
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There seems to be some confusion in the diagram. It shows a "velocity" in m3/s, asks about another such in the same units, but also quotes a "flow rate" in those units at the "exhaust temperature". How does that relate to the two velocities?
I have a suspicion the two "velocities" are supposed to be m/s. Given the diameter, that would seem to be consistent with the volumetric flow rate. If so, it makes the question much easier; you can ignore most of the information.
 
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rude man said:
I think you're right. That formula applies to incompressible fluids like water. The flue gases are of course compressible.

I'm afraid I must leave this one to other helpers.
Thank you very much, now I am looking the gas equation also that can apply this issue.
 
haruspex said:
There seems to be some confusion in the diagram. It shows a "velocity" in m3/s, asks about another such in the same units, but also quotes a "flow rate" in those units at the "exhaust temperature". How does that relate to the two velocities?
I have a suspicion the two "velocities" are supposed to be m/s. Given the diameter, that would seem to be consistent with the volumetric flow rate. If so, it makes the question much easier; you can ignore most of the information.
Oh!, that's my mistake, the right should be (m/s) as you said.
Thank you very much
 
Suradanai said:
Oh!, that's my mistake, the right should be (m/s) as you said.
Thank you very much
"The right"? Do you mean the "flow rate"? I would have thought that was m3/s, and the two "velocities" should be m/s.
 
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