Can someone me on an equilibrium problem?

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A user seeks help with a physics problem involving two concurrent forces acting on a 50.0 kg box, needing to find a third force for equilibrium. They attempted to calculate the resultant forces using sine and cosine functions but encountered confusion regarding the principle of deficiencies and the sigma notation for summing forces. Clarification was provided that the sigma symbol represents the sum of all forces, not calculus. The user expressed gratitude for the assistance received. Understanding the principle of inertia was also briefly mentioned as a related concept.
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i have my physics exam tomorrow and i need help understanding this problem because i got this wrong on a previous test

Homework Statement


Two concurrent forces are acting on a box with a mass of 50.0 kg. One force is 555 N acting at an angle of 140 degrees; the other force is 785 N at an angle of 200 degrees. What third force would have to be added to the situation to produce a state of equilibrium?

Homework Equations


f= ma i guess... i didnt use it though


The Attempt at a Solution


555sin(40)-785sin(20) >> V
-555cos(40)-785cos(20) >> H
then i square rooted V^2 + H^2
then i tan^-1(V/H)
and i got some negative funky number
 
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Use the principle of deficiencies.
 


mtayab1994 said:
Use the principle of deficiencies.

what is that?
 
\sum(F)=0
 
mtayab1994 said:
\sum(F)=0

i probably sound really stupid saying this but.. is that calculus? because if it is i am currently only in algebra II
 
darlingdarlin said:
i probably sound really stupid saying this but.. is that calculus? because if it is i am currently only in algebra II

No that's not calculus that sign (sigma) stands for the sum of all forces.
 
mtayab1994 said:
No that's not calculus that sign (sigma) stands for the sum of all forces.

okay thank you!
i really appreciate it
 
darlingdarlin said:
okay thank you!
i really appreciate it

Did you learn how to use the principle of inertia?
 

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