Can TdS be computed using an area, time double integral of heat flux density?

AI Thread Summary
The discussion explores whether the TdS (temperature times entropy) of a system can be calculated using a double integral of heat flux density over area and time. It raises the question of how this calculation might change in the context of a growing black hole, where heat is presumed to flow inward rather than outward. The potential for the double integral to yield an opposite sign in such scenarios is considered, suggesting that a black hole could act as a reducer of TdS. This leads to further inquiries about the implications of black hole thermodynamics on entropy calculations. The conversation highlights the complexity of thermodynamic principles in extreme gravitational fields.
kmarinas86
Messages
974
Reaction score
1
Can the TdS by a system be calculated by taking the area, time double integral of the heat flux density?

If so, is it possible that this double-integral would take on an opposite sign if inside there was a dominating, growing black hole, where, I would presume, heat flows inwards, and not outwards? The divergence of the field inside the surface would therefore have an opposite sign, so would a growing blackhole therefore be a TdS reducer?
 
Last edited:
Physics news on Phys.org
Anyone?
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top