Can the Magnetic Field Be Determined Using Biot-Savart Law Superposition?

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The discussion focuses on determining the magnetic field along the z-axis from a conductor loop with a constant current. It confirms that the magnetic fields from different segments can be calculated and summed using the Biot-Savart Law. Segments 1 and 3 align with the z-axis, and their contributions to the magnetic field can be analyzed using the right-hand rule. A complete circle produces a magnetic field directed solely along the z-axis due to radial symmetry, while a semicircle results in a field directed in both the z- and y-directions, as contributions along the x-axis cancel out. This analysis serves as preparation for upcoming exams.
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For the following conductor loop, determine the magnetic field along the ##z##-axis, which passes through the center of the conductor loop and is perpendicular to it.
The conductor loop consists of an infinitely long wire through which a constant current ##I## runs.
Is it possible to determine the magnetic fields in the different sections ## \vec B_i## with ## i \in \{ 1,2,3 \}## and then calculate the total field by ## \vec B= \sum \limits_{i=1}^3 \vec B_i##?

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Yes.
Is this homework ?

LeoJakob said:
... determine the magnetic field along the z-axis, ...
At all points on the z-axis, or at the origin in the direction of the z-axis ?

Segments 1 and 3 are in line with the z-axis. Apply the right-hand rule.
What direction will the field from segments 1 and 3 be on the z-axis ?

What is the field on the central axis of a circle ?
What is the field on the central axis of a semicircle ?
 
Thank you ! :)

It is an exercise to solve for the upcoming exams:

-segment 1 and 2 produce the same magnetic field at a point on the z axis
- a whole circle on the central x-axis would create a magnetic field that points only in the z-direction because of the radial symmetry
- a semicircle
on the central x-axis would create a magnetic field that points only in the z- and y-direction because the contributions on the x-axis cancel out
 
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