Can This Table Hold a 1500 lb Axle?

AI Thread Summary
The discussion revolves around whether a table can support a 1500 lb axle, emphasizing the need to analyze the forces acting on the structure and ensure they do not exceed the yield strength of the materials. Participants suggest using structural mechanics software like ABAQUS or NASTRAN for detailed analysis. One contributor performs a rough calculation, determining that the stress on the axle locator plates is 3.5 MPa, significantly lower than the yield strength of structural steel at 250 MPa. This indicates that the table is structurally safe to hold the axle. Overall, the conversation highlights the importance of stress analysis and safety factors in engineering design.
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See the pdf here: www.ellipticinc.com/table.pdf

Will this table must be able to hold a 1500 lb axle? Just help me a bit and get me started. I have no idea where to begin.
 
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I believe you would have to find out how the forces would act within the structure and see if any one of those forces exceed the yielding strength of the materials being used.
 
Hello,

Could you provide a little more detail and maybe do the 1st few steps. Are there any similar examples like this one on internet.

Thanks.
 
You need to look at stresses in various parts of the fixture to see if any exceed the yield stress for the materials involved. As it is heavy and injury is a possibility, there should be a safety factor involved.

For something of this nature I would use a structural mechanics program of some sort like ABAQUS, NASTRAN, etc.
 
Can someone please check my work:

ok. if i do this by thumb rule then the structure is safe enough to hold the axle. How? now consider the load of 1500 lb = 6672 N is equally distributed among the two axle locator plates. Now since complete dimension are not given so from the observation of the angle locator plates, roughly an area of (1 inch * 1.5 inch)*2 is in contact with the axle. Now axle locator is the critical load bearing member in the table assembly. So it will be taking the maximum stress. formula for stress is, stress =force/area

stress = 6672 N / 2*950 square mm = 3.5 Mpa

Normally structural steel has a yield strength of 250 Mpa. So the calculated stress (3.5 Mpa) is very much lower than the yield stress. So the structure is safe.

Regards
 
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