Can tubes be minimal surfaces?

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Homework Statement



Prove that there are no tubes that are minimal surfaces

Homework Equations


F(u, v) = γ(u) + R(cosuN(v) + sinuB(v))


The Attempt at a Solution



A tube is defined to be the surface formed by drawing circles with constant radius in the normal plane in a space curve.

I know that a minimal surface is a surface with a mean curvature of zero. So to prove the tubes aren't minimal surfaces, I need to show that the mean curvature is non-zero. I just don't know what the first step to take here is. Any tips/suggestions?
 
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Assume the curve is given by the parametric equation x= f(t), y= g(t), z= h(t). Can you write parametric equations for a point on the tube?
 
Edited the first post for a relevant equation.

Wouldn't x=rcost, y=rsint and z=t?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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