Can you assume that Jupiter has a circular orbit?

AI Thread Summary
Jupiter's orbit can be approximated as circular due to its small eccentricity, allowing the assumption that r is approximately equal to a. Spacecraft traveling to the outer planets achieve speeds 1.5 times that of Jupiter, resulting in hyperbolic orbits around the Sun. The Vis-Viva equation is relevant for calculating the velocities and energies of both the spacecraft and Jupiter. The discussion highlights the importance of understanding the semimajor axis in relation to parabolic and hyperbolic trajectories. Accurate calculations are essential for mission planning and understanding orbital dynamics.
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When it is about the same distance from Jupiter, spacecraft on a mission to the outer planets has a speed that is 1.5 times the speed of Jupiter in its orbit. Why does the orbit of the spacecraft about the sun follow a hyperbolic orbit?

Can you assume that Jupiter has a circular orbit? So far I've tried caltulating the total energies of the spacecraft and of Jupiter but I don't think that's correct.
 
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Use the Vis-Viva equation

<br /> <br /> V=\sqrt{\frac{2}{r}-\frac{1}{a}}<br /> <br />

It's a safe assumption (unless they give it to you explicitly) that the eccentricity of planetary orbits are very small. That means that r~=a.

What is the semimajor axis of a parabolic (or hyperbolic) orbit? You can solve for escape velocity with that.
 
I made a mistake.

Vis Viva is:

<br /> <br /> V=\sqrt{\mu*(\frac{2}{r}-\frac{1}{a})}<br /> <br />

Where mu is the gravitational parameter, G*M or 398600.4 km^3/sec^2
 
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