Can You Calculate Reynolds Number with Limited Data on a Scaled Missile Model?

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Reynolds number can be calculated for a scaled missile model using the temperature of the water, the missile's dimensions, and its velocity. The viscosity of the water can be derived from the temperature, which is essential for the calculation. A characteristic length can be chosen based on the missile's design, even if it differs from standard shapes. For a 1:10 scale model, the existing scale already accounts for the length in the Reynolds number equation. Further study on fluid dynamics and similitude principles can enhance understanding of these calculations.
eddierolling
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hi

i have to find out the reynolds number for a missile launched from a sub.

i only have the temperature of the water, the dimensions of the missile and the velovity of a model of the of the actual missile at a scale of 1:10

i havn't given any quantities because i don't want a solution.

i need to know if i can solve Reynolds number from the information given in the question and if so where to find the information i need so i can study it for my self.

any help anyone can give will be greatly appriciated.

thanks
 
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Recall that Reynolds number is
Re = \frac{Vl}{\nu}
Where l is a rather arbitrary characteristic length. From the temperature of the water, you can calculate the viscosity, and you say that you're given the velocity of the missile.

That only leaves the length. Remember this is problem dependent and doesn't necessarily have to be the standard diameter that's used for pipe flow. Use a characteristic length that you think makes sense.
 
I'm confused about this as well. I have a very odd "horseshoe" shaped design. I would like to calculate the drag under the ocean surface at a speed of 20 knots. I have a 1:10 scale model, but no good way of testing it at speed. Do I test it in water at the appropriate temperature going at only 2 knots and then scale the Reynolds number equation by multiplying the length by 10? How does mass affect the Reynolds number? I've watched Ascher Shapiro's videos at length and I still don't get it!
 
No, your scale is already there, 1:10. You don't need a characteristic length because you have the scale change. See
http://en.wikipedia.org/wiki/Similitude_(model )

For more information
 
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