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Can you please help me with this thevenin problem ?

  • Thread starter ujnikm
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  • #1
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Can you please help me with this thevenin problem ???

Please guys can you help me with this??
http://forum.allaboutcircuits.com/cache.php?url=http://s14.postimage.org/9eysbodr5/image.png [Broken]
I set all sources to 0 so we have Rth=3.667 KΩ
then using superposition and remove the current source and replace it with open circuit so we have Vth1 =-3.333 V
then remove the voltage source and replace it with short circuit so we have Vth2=25 V
so Vth=25-3.3333=21.667 V

other friends tell me that Vth2=30 V

what's the correct ??
 
Last edited by a moderator:

Answers and Replies

  • #2
gneill
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20,698
2,704


Please guys can you help me with this??
http://forum.allaboutcircuits.com/cache.php?url=http://s14.postimage.org/9eysbodr5/image.png [Broken]
I set all sources to 0 so we have Rth=3.667 KΩ
then using superposition and remove the current source and replace it with open circuit so we have Vth1 =-3.333 V
then remove the voltage source and replace it with short circuit so we have Vth2=25 V
so Vth=25-3.3333=21.667 V

other friends tell me that Vth2=30 V

what's the correct ??
Listen to your friends :wink:
 
Last edited by a moderator:
  • #3
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Listen to your friends :wink:
why????
 
  • #4
gneill
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20,698
2,704


why????
Show your work for finding Vth2. Remember that terminals A-B are an open circuit when finding the Thevenin voltage.
 

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