- #1
dbn
- 3
- 0
if you can solve ax^2-40x+40=0 for a and x that would be great
use this formula [tex]\frac{-b ^+_- \sqrt{b^2 - 4ac}}{2a}[/tex]where a=a, b=-40 and c=40if you can solve ax^2-40x+40=0 for a and x that would be great
phreak said:I bet there are millions of answers for this one.
Now, while the others have shown how to find x given a, here's how you may find the a-value for any choice of x-value:dbn said:i still don't get it can some one give me a walk through on how to use them with this problem/
The formula for solving a quadratic equation in the form of Ax^2 + Bx + C = 0 is x = (-B ± √(B^2-4AC)) / 2A.
You should use the quadratic formula if the equation cannot be easily factored. If the equation is in the form of Ax^2 + Bx + C = 0, and A, B, and C are all non-zero values, then you can use the quadratic formula.
Step 1: Identify the values of A, B, and C in the equation Ax^2 + Bx + C = 0.Step 2: Substitute these values into the quadratic formula: x = (-B ± √(B^2-4AC)) / 2A.Step 3: Simplify the equation.Step 4: Use a calculator to find the solutions, if necessary.Step 5: Check your solutions by plugging them back into the original equation to make sure they work.
The discriminant is the part of the quadratic formula under the square root sign: B^2-4AC. It is used to determine the number of solutions to a quadratic equation. If the discriminant is positive, there will be two real solutions. If it is zero, there will be one real solution. And if it is negative, there will be no real solutions.
The possible solutions to this equation can be found by using the quadratic formula: x = (-B ± √(B^2-4AC)) / 2A. If the discriminant is positive, there will be two real solutions. If it is zero, there will be one real solution. And if it is negative, there will be no real solutions.