Cannon shot on airless planet with x gravity

AI Thread Summary
The discussion revolves around calculating the speed of a projectile fired from a cannon on an airless planet as it passes an orbiting satellite. The planet's parameters include a radius of 5.0 x 10^6 m and a mass of 2.6 x 10^24 kg, with the cannon firing at 3800 m/s. The user is struggling with the energy conservation equation and is encountering negative values under the square root, indicating a potential error in their calculations. Another participant suggests that the user may have mismanaged the signs when rearranging the equation. The overall focus is on resolving the projectile's speed using gravitational potential energy principles.
Mugen112
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I've been struggling with this problem for over two hours...PLEASE HELP!

Homework Statement


A huge cannon is assembled on an airless planet. The planet has a radius of 5.0 \times 10^{6}\;{\rm m} and a mass of 2.6 \times 10^{24}\;{\rm kg}. The cannon fires a projectile straight up at 3800 m/s.

An observation satellite orbits the planet at a height of 700 km. What is the projectile's speed as it passes the satellite?

Homework Equations


1/2mv22 - GMm/r+y2 = 1/2mv12- GMm/R



The Attempt at a Solution



I'm trying to use that equation and solve for y2. I keep coming up with a negative number.

v2= sqroot[v12 - (2GM/R) - (2GM/R+y2)]

you can see that when u subtract, you will get a negative under the root... I am going to go crazy. any help is appriciated.
 
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Hi Mugen112,

Mugen112 said:
I've been struggling with this problem for over two hours...PLEASE HELP!

Homework Statement


A huge cannon is assembled on an airless planet. The planet has a radius of 5.0 \times 10^{6}\;{\rm m} and a mass of 2.6 \times 10^{24}\;{\rm kg}. The cannon fires a projectile straight up at 3800 m/s.

An observation satellite orbits the planet at a height of 700 km. What is the projectile's speed as it passes the satellite?

Homework Equations


1/2mv22 - GMm/r+y2 = 1/2mv12- GMm/R



The Attempt at a Solution



I'm trying to use that equation and solve for y2. I keep coming up with a negative number.

v2= sqroot[v12 - (2GM/R) - (2GM/R+y2)]

I don't believe this equation is correct. When you moved the potential energy term from the left side to the right its sign should have become positive.

you can see that when u subtract, you will get a negative under the root... I am going to go crazy. any help is appriciated.
 
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