Canoeist Question: Crossing a 200m River & Directions

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Homework Statement



a canoeist wishes to cross a 200m river to get to the campsite directly across from the starting point. he can paddle 2.5m/s in still water, and the current has a speed of 1.2m/s how far downstream would the canoeist land if headed directly across the river.
and in what direction should the canoeist head in order to arrive directly across from the starting point.

how would i do this?
 
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hi menal! :smile:
menal said:
… how would i do this?

darw a vector triangle :wink:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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