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## Homework Statement

Consider a charged parallel-plate capacitor. How can its capacitance be halved?

Check all that apply.

Double the charge.

Double the plate area.

*Double the plate separation.

*Halve the charge.

*Halve the plate area.

Halve the plate separation

## Homework Equations

C = Q/V

## The Attempt at a Solution

I know for sure that the capacitance can be reduced if the area decreases and separation increases. The part I am unsure is if the capacitance is decreased if the charge is decreased, although I am leaning more towards it does, since there will be less charge spread around the area of the plate. Thanks in advance.