1. The problem statement, all variables and given/known data Consider a charged parallel-plate capacitor. How can its capacitance be halved? Check all that apply. Double the charge. Double the plate area. *Double the plate separation. *Halve the charge. *Halve the plate area. Halve the plate separation 2. Relevant equations C = Q/V 3. The attempt at a solution I know for sure that the capacitance can be reduced if the area decreases and separation increases. The part I am unsure is if the capacitance is decreased if the charge is decreased, although I am leaning more towards it does, since there will be less charge spread around the area of the plate. Thanks in advance.