Capacitance for a parallel RC circuit

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SUMMARY

The discussion centers on calculating the values of the resistor and capacitor in a parallel RC circuit with a Zener diode, maintaining a voltage of 4.7V and a power of 5mW. The resistance was determined to be 4.4k Ohms using the formula P=V^2/R. The challenge lies in calculating the capacitance, where the user derived two equations: Ic=CdV/dt and Ir=V/R, but requires further guidance on solving for capacitance. Additional context about the circuit's connection to a rectifier is also sought.

PREREQUISITES
  • Understanding of Ohm's Law and power calculations
  • Familiarity with capacitor charging equations
  • Knowledge of Zener diode operation
  • Basic principles of AC circuits and rectification
NEXT STEPS
  • Study the relationship between current and capacitance in RC circuits
  • Learn about Zener diode voltage regulation techniques
  • Explore the effects of frequency on capacitor behavior in AC circuits
  • Investigate full-wave and half-wave rectification impacts on circuit performance
USEFUL FOR

Electrical engineering students, hobbyists designing RC circuits, and anyone involved in power supply design and analysis.

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Homework Statement



A circuit consists of a Zener diode, capacitor and resistor in parallel. Voltage to be maintained across the components is 4.7V, power 5mW. Find the values for resistor and capacitor

Homework Equations



(Below)

The Attempt at a Solution



I found the resistance by taking P=V^2/R, and using the given values for P and V, R=4.4k(Ohms). I have a problem with finding the capacitance value.
I found the current for the resistor. But there're 2 unknowns now, the capacitor value and the Ic. I've come up to the point where two equations are obtained: Ic=CdV/dt; Ir=V/R. How do I proceed from here to get C? Is this the correct way of approaching this?

Thanks.
 
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The problem is incomplete. Is this circuit connected to the output of a rectifier? If so, is it full wave or half wave? What is the peak voltage of the rectified voltage. (I assume the frequency is 60 Hz).
 

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