Capacitance of Capacitor

1. Mar 1, 2012

DrunkApple

1. The problem statement, all variables and given/known data
A capacitor is constructed from two square
metal plates. A dielectric $\kappa$ = 4.61 fills the
upper half of the capacitor and a dielectric
$\kappa$ = 6.9 fills the lower half of the capacitor.
Neglect edge effects. Calculate the capacitance C of the device.

2. Relevant equations
C$_{TOP}$ = $\kappa$$\epsilon$A/d
C$_{bottom}$ = $\kappa$$\epsilon$A/d
C$_{total}$ = C$_{TOP}$ + C$_{BOTTOM}$

3. The attempt at a solution
C$_{TOP}$ = $\kappa$$\epsilon$A/d
= 4.61(8.85419*10$^{-12}$)(.12$^{2}$)/0.0005
= 1.175553098*10$^{-9}$
C$_{bottom}$ = 6.9(8.85419*10$^{-12}$)(.12$^{2}$)/0.0005
= 1.759504637*10$^{-9}$
C$_{total}$ = 2.935057735*10$^{-9}$
Is this correct?

2. Mar 1, 2012

Staff: Mentor

Ummm. Plate size? Plate separation? Are the plates oriented vertically or horizontally?