Capacitance of three coaxial metal tubes

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Homework Help Overview

The problem involves finding the capacitance per unit length of three long coaxial metal tubes with specified radii and a wire connecting the innermost and outermost tubes. The context is within electrostatics, specifically focusing on capacitance and potential differences in cylindrical geometries.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of the problem, particularly the implications of the wire connecting the tubes and how charge distribution occurs. There is exploration of potential differences between the tubes and the definition of capacitance in this context.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about charge distribution and potential differences. Some guidance has been offered regarding the equipotential nature of the connected tubes, but no consensus has been reached on the overall approach to finding the capacitance.

Contextual Notes

There is uncertainty regarding the distribution of charge and the implications of the wire connecting the innermost and outermost tubes. Participants are also grappling with the definition of capacitance as it applies to this specific configuration.

boardbox
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Homework Statement



Find the capacitance per unit length of three long coaxial metal tubes, with radii
a < b < c . A wire connects the innermost and outermost tubes (radii a and c).

Homework Equations





The Attempt at a Solution



I'm a little confused as to how I should set this up. What confused me is the wire that runs between the innermost and outermost tube. My thought is that it just makes the two tubes one big conductor. If that's the case and I put some charge on the conductor, how does it get distributed? Could I just put a charge on it and say the charge on the innermost tube is the area of the innertube over the area of the whole conductor times the charge?
 
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boardbox said:
Could I just put a charge on it and say the charge on the innermost tube is the area of the innertube over the area of the whole conductor times the charge?

I don't think you can assume that. However, if the two cylinders are connected by a conducting wire, you can say that they are equipotentials.
 
Alright well let me think this out for a second.

What I'm after is the potential from c to a, after that the problem is simple. That's going to be V(c) - V(a). Well V changes, so taking two steps V(c) - V(b) + V(b) - V(a). If V(c) = V(a) then I get zero potential. That seems a little silly to me, also means I'm dividing by zero in the next step, so I don't think that's right.

Here's another thought and this strikes me as a bit less silly. Say I have some charge on the innermost cylinder and some other charge on the middle cylinder. I could find the potential difference between the two. Now I know the outermost cylinder has the same potential at the innermost one, which means that the potential difference between it and the middle cylinder is the same as the difference between the middle cylinder and inner cylinder. So the potential of the set is just two times the potential between the inner and middle cylinder.
 
boardbox said:
What I'm after is the potential from c to a, after that the problem is simple.

Why do you say that? What is the applicable definition of capacitance here?
 

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