LuxFestinus said:
So from what I understand from all this is that as the frequency changes so does impedance. Then increased leakage with increased frequency occurs because of a change in impedance? I thought signals bled across wire traces more with increased frequency. Seems like they would do this less if resistance was higher.
Lux, I share Supernova's frustration here. Do you know the differential equation that defines the behavior of voltage and current for a capacitor? That shows the frequency dependence of impedance directly. Check out any basic EE or E&M text for a tutorial on caps.
The basic equation for a capacitor is written I = C dv/dt
That means that the current "through" the capacitor (the displacement current, not any resistive leakage current) is proportional to the capacitance and also proportional to the rate of change of the voltage with respect to time. Given a constant C and a constant amplitude sine wave, the higher the frequency of the sine wave, the higher dv/dt is. Thus, the displacement current through a capacitor is proportional to the frequency of excitation, and since Z = dV/dI, the impedance of a capacitor is inversely proportional to frequency and inversely proportional to C.
And as Supernova says, if you add into your model the series inductance associated with the real capacitor (whether from ESL inside an electrolytic cap, or from the leads and traces going into SMT ceramic caps), the inductive impedance (which is proportional to frequency and L, as opposed to the impedance of capacitors, which is inversely related to frequency and C) will make the overall impedance have a different shape from just the ideal capacitor. This is easiest to see if you have either a SPICE package to simulate the series L-C connection, or access to an impedance analyzer like an HP 4194. Plot Z(f) for some different combinations of R,L,C with either of these tools, and you will start to get a better feel for the "impedance" characteristics of real circuits.